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Proof step 17 from proof add-in-fskey (previous step)

r -- sk ∈ addarray(r, ty, vals, st), is_fskey(sk) ⊦ sk = _length, sk = _type, r -- sk ∈ st

User applied rule induction

And obtained the following new goals

Proof step 16:
r -- sk ∈ addarray(r, ty, vals, st) ∧ is_fskey(sk), ∀ st, ty, sk, r, vals0. # vals0 < # vals → (r -- sk ∈ addarray(r, ty, vals0, st) ∧ is_fskey(sk) → sk = _length ∨ sk = _type ∨ r -- sk ∈ st) ⊦ sk = _length ∨ sk = _type ∨ r -- sk ∈ st

Rule argument

[INDHYPARG : [STANDARDINDUCTIONTYPE : ], true, false, # vals, [] → [], <]

Additional information

[[CONCRETESIMPRULES : ([CSIMPLESSPRED : <])], [EXTRATERMS : (# vals)]]