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Proof step 18 from proof add-in-fskey (conclusion)

⊦ is_fskey(sk) ∧ sk ≠ _length ∧ sk ≠ _type → (r -- sk ∈ addarray(r, ty, vals, st) ↔ r -- sk ∈ st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ rk ∈ st → rk ∈ addarray(r, ty, vals, st)
Proof step 2:
⊦ r ∈ addarray(r, ty0, vals, st)
Proof step 17:
r -- sk ∈ addarray(r, ty, vals, st), is_fskey(sk) ⊦ sk = _length, sk = _type, r -- sk ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]