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Proof step 11 from proof addarray-mklist-02 (previous step)

n→i(m) + 1 > 0, ∀ r, val, st. addarray(r, mklist(val, m), 0, st) = addarray(r, val, n→i(m), st) ⊦ addarray(r, mklist(val, m + 1), 0, st) = (addarray(r, val, n→i(m) + 1 - 1, st)[r -- (n→i(m) + 1 - 1) ', val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
∀ r, val, st. addarray(r, mklist(val, m), 0, st) = addarray(r, val, n→i(m), st) ⊦ addarray(r, mklist(val, m + 1), 0, st) = (addarray(r, val, n→i(m), st)[r -- n→i(m) ', val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 ≤ n→i(n)], [CSIMPSEQ : ⊦ (~1) < i ↔ 0 ≤ i], [CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0], [CSIMPSEQ : ⊦ i > j ↔ j < i], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + 0 = i], [CSIMPSEQ : ⊦ ((* i)) + i0 - ((* j)) = (i - j) + i0])]]