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Proof step 12 from proof addarray-mklist-02 (previous step)

∀ r, val, st. addarray(r, mklist(val, m), 0, st) = addarray(r, val, n→i(m), st) ⊦ addarray(r, mklist(val, m + 1), 0, st) = addarray(r, val, n→i(m) + 1, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ i > 0 → addarray(r, val, i, st) = (addarray(r, val, i - 1, st)[r -- (i - 1) ', val])
Proof step 11:
n→i(m) + 1 > 0, ∀ r, val, st. addarray(r, mklist(val, m), 0, st) = addarray(r, val, n→i(m), st) ⊦ addarray(r, mklist(val, m + 1), 0, st) = (addarray(r, val, n→i(m) + 1 - 1, st)[r -- (n→i(m) + 1 - 1) ', val])

Rule argument

[crewrite-arg: addarray-rec , F , [st, i, val, r] → [st, n→i(m) + 1, val, r] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i > j ↔ j < i], [CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0], [CSIMPSEQ : ⊦ (~1) < i ↔ 0 ≤ i], [CSIMPSEQ : ⊦ 0 ≤ n→i(n)], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j = j + i])], [EXTRATERMS : (st, n→i(m) + 1, val, r)]]