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Proof step 4 from proof at-init (previous step)

is_fskey(sk) ⊦ (addarray(r, vals, j, st[r -- sk, val])[r -- i ']) = (addarray(r, vals, j, st)[r -- i '])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_fskey(sk) → addarray(r, vals, i, st[r0 -- sk, val]) = (addarray(r, vals, i, st)[r0 -- sk, val])
Proof step 3:
is_fskey(sk), is_fskey(sk) ⊦ (addarray(r, vals, j, st)[r -- sk, val][r -- i ']) = (addarray(r, vals, j, st)[r -- i '])

Rule argument

[crewrite-arg: init-switch , F , [val, sk, r0, st, i, vals, r] → [val, sk, r, st, j, vals, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (val, sk, r, st, j, vals, r)]]