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Proof step 5 from proof at-init (conclusion)

⊦ is_fskey(sk) → (addarray(r, vals, j, st[r -- sk, val])[r -- i ']) = (addarray(r, vals, j, st)[r -- i '])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
is_fskey(sk) ⊦ (addarray(r, vals, j, st[r -- sk, val])[r -- i ']) = (addarray(r, vals, j, st)[r -- i '])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]