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Proof step 7 from proof getarray-addarray-06 (previous step)

i ≤ n→i(n), 0 < i, n < i→n(i) ⊦ i = 0, (addarray(r, ty, i, st)[r -- n→i(n) ']) = initial_value(ty), n = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
0 ≤ i ⊦ ((* m)) < i→n(i) ↔ n→i(m) < i

Rule argument

[speclemmaarg: 0 ≤ i ,((* m)) < i→n(i) ↔ n→i(m) < i ,[i, m] → [i, n] ,F ,intnat , ,num-i2n-ls-02 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i < j → ¬ j < i], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ i ≠ j → (i ≤ j ↔ i < j)], [CSIMPSEQ : ⊦ i < j → (¬ ¬ j ≤ i ↔ false)])], [EXTRATERMS : (i, n)]]