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Proof step 8 from proof getarray-addarray-06 (previous step)

¬ (0 ≤ n→i(n) ∧ n→i(n) < i), n < i→n(i), 0 < i ⊦ (addarray(r, ty, i, st)[r -- n→i(n) ']) = initial_value(ty), i = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
i ≤ n→i(n), 0 < i, n < i→n(i) ⊦ i = 0, (addarray(r, ty, i, st)[r -- n→i(n) ']) = initial_value(ty), n = 0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 < n ↔ n ≠ 0], [CSIMPSEQ : 0 ≤ i ⊦ ((* i)) < n→i(n) ↔ i→n(i) < n], [CSIMPFORWARD : ⊦ i ≤ j ∧ 0 < i → 0 < j], [CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i], [CSIMPSEQ : ⊦ 0 ≤ n→i(n)])]]