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Proof step 21 from proof getbar-addbar-02 (previous step)

n < i→n(j) ∧ i→n(i) + i→n(j) ≤ # ints, 0 < j, 0 ≤ i, i→n(i) + i→n(j) < # ints, i + j ≤ n→i(# ints), n < i→n(j), n < # sublist(i→n(i), i→n(j), ints) ⊦ j = 0, ints = [], (mkjavavalues(is2bs(ints))[i→n(i) + n]) .byteval = i2b(ints[i→n(i) + n]), sublist(i→n(i), i→n(j), ints) = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
0 < j, 0 ≤ i, i→n(i) + i→n(j) < # ints, i + j ≤ n→i(# ints), n < i→n(j), n < # sublist(i→n(i), i→n(j), ints) ⊦ j = 0, ints = [], (mkjavavalues(is2bs(ints))[i→n(i) + n]) .byteval = i2b(ints[i→n(i) + n]), sublist(i→n(i), i→n(j), ints) = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m < n → m ≤ n], [CSIMPSEQ : ⊦ m + n = n + m])]]