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Proof step 22 from proof getbar-addbar-02 (previous step)

0 < j, 0 ≤ i, i→n(i) + i→n(j) < # ints, i + j ≤ n→i(# ints), n < i→n(j), n < # sublist(i→n(i), i→n(j), ints) ⊦ j = 0, ints = [], (mkjavavalues(is2bs(ints))[i→n(i) + n]) .byteval = i2b(sublist(i→n(i), i→n(j), ints)[n]), sublist(i→n(i), i→n(j), ints) = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 18:
⊦ n0 < n ∧ m + n ≤ # ints → (sublist(m, n, ints)[n0]) = ints[m + n0]
Proof step 21:
n < i→n(j) ∧ i→n(i) + i→n(j) ≤ # ints, 0 < j, 0 ≤ i, i→n(i) + i→n(j) < # ints, i + j ≤ n→i(# ints), n < i→n(j), n < # sublist(i→n(i), i→n(j), ints) ⊦ j = 0, ints = [], (mkjavavalues(is2bs(ints))[i→n(i) + n]) .byteval = i2b(ints[i→n(i) + n]), sublist(i→n(i), i→n(j), ints) = []

Rule argument

[speclemmaarg: ,n0 < n ∧ m + n ≤ # ints → (sublist(m, n, ints)[n0]) = ints[m + n0] ,[n0, ints, n, m] → [n, ints, i→n(j), i→n(i)] ,F ,list-del ,intlista ,sublist-at ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ m < n ↔ n ≤ m], [CSIMPSEQ : ⊦ m < n → (n ≤ m ↔ false)], [CSIMPSEQ : ⊦ ¬ m ≤ n ↔ n < m], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ m < n → ¬ n < m])], [EXTRATERMS : (n, ints, i→n(j), i→n(i))]]