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Proof step 6 from proof is_array-addarray-any (previous step)

0 ≤ j, j < n→i(# vals), type∃(str, ty), # vals ≤ i→n(j) ⊦ r = jvmref, ty .jtelemtype = abstract_type, ty .jtelemtype = void_type, vals = [], okval(vals[i→n(j)], ty), is_array(r, addarray(r, ty, vals, st)), vals[i→n(j)] ∈ vals

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
0 ≤ i ⊦ ((* i)) < n→i(n) ↔ i→n(i) < n

Rule argument

[speclemmaarg: 0 ≤ i ,((* i)) < n→i(n) ↔ i→n(i) < n ,[n, i] → [# vals, j] ,F ,intnat , ,num-n2i-ls-02 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m ≤ n → (n < m ↔ false)])], [EXTRATERMS : (# vals, j)]]