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Proof step 7 from proof is_array-addarray-any (previous step)

¬ i→n(j) < # vals, 0 ≤ j, j < n→i(# vals), type∃(str, ty) ⊦ r = jvmref, ty .jtelemtype = abstract_type, ty .jtelemtype = void_type, vals = [], okval(vals[i→n(j)], ty), is_array(r, addarray(r, ty, vals, st)), vals[i→n(j)] ∈ vals

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
0 ≤ j, j < n→i(# vals), type∃(str, ty), # vals ≤ i→n(j) ⊦ r = jvmref, ty .jtelemtype = abstract_type, ty .jtelemtype = void_type, vals = [], okval(vals[i→n(j)], ty), is_array(r, addarray(r, ty, vals, st)), vals[i→n(j)] ∈ vals

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ m < n ↔ n ≤ m])]]