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Proof step 14 from proof newref-1dim (previous step)

rk ∈ addarray(r, ty, i, st), ∀ rk0. rk0 ∈ st → rk0 .ref ≠ rk .ref ⊦ rk .ref = jvmref, r = rk .ref

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 13:
rk = r0 -- sk, rk ∈ addarray(r, ty, i, st), ∀ rk0. rk0 ∈ st → rk0 .ref ≠ r0 ⊦ r0 = jvmref, r = r0

Rule argument

[speclemmaarg: ,r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk ,[rk, r, sk] → [rk, r0, sk] ,T ,refkey , ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ r = rk .ref ∧ sk = rk .key ↔ rk = r -- sk])], [EXTRATERMS : (rk, r0, sk)]]