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Proof step 15 from proof newref-1dim (previous step)

r ≠ r0 ∧ (∀ rk. rk ∈ st → rk .ref ≠ r0) ⊦ ∀ rk. rk ∈ addarray(r, ty, i, st) → rk .ref ≠ r0, r0 = jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
rk ∈ addarray(r, ty, i, st), ∀ rk0. rk0 ∈ st → rk0 .ref ≠ rk .ref ⊦ rk .ref = jvmref, r = rk .ref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]