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Proof step 81 from proof putarray-addarray-one (previous step)

is_fskey(sk) ∧ sk ≠ _length ∧ sk ≠ _type, is_reftype(ty) ⊦ r -- sk ∈ addarray(r, ty, n→i(# vals) + 1, st) ∨ is_indexkey(sk) ∧ 0 < sk .index ∧ sk .index ≤ n→i(# vals) ↔ r -- sk ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 77:
⊦ rk ∈ st → rk ∈ addarray(r, ty, i, st)
Proof step 80:
is_fskey(sk), is_reftype(ty), r -- sk ∈ addarray(r, ty, n→i(# vals) + 1, st) ∨ is_indexkey(sk) ∧ 0 < sk .index ∧ sk .index ≤ n→i(# vals) ⊦ sk = _type, sk = _length, r -- sk ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]