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Proof step 82 from proof putarray-addarray-one (previous step)

is_reftype(ty) ⊦ r -- sk ∈ addarray(r, ty, n→i(# vals) + 1, st) ∨ is_indexkey(sk) ∧ 0 < sk .index ∧ sk .index ≤ n→i(# vals) ↔ r -- sk ∈ addarray(r, ty, refval(jvmref) ' + vals, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 63:
⊦ is_fskey(sk) ∧ sk ≠ _length ∧ sk ≠ _type → (r -- sk ∈ addarray(r, ty, vals, st) ↔ r -- sk ∈ st)
Proof step 76:
¬ (is_fskey(sk) ∧ sk ≠ _length ∧ sk ≠ _type), is_reftype(ty) ⊦ r -- sk ∈ addarray(r, ty, n→i(# vals) + 1, st) ∨ is_indexkey(sk) ∧ 0 < sk .index ∧ sk .index ≤ n→i(# vals) ↔ r -- sk ∈ addarray(r, ty, refval(jvmref) ' + vals, st)
Proof step 81:
is_fskey(sk) ∧ sk ≠ _length ∧ sk ≠ _type, is_reftype(ty) ⊦ r -- sk ∈ addarray(r, ty, n→i(# vals) + 1, st) ∨ is_indexkey(sk) ∧ 0 < sk .index ∧ sk .index ≤ n→i(# vals) ↔ r -- sk ∈ st

Rule argument

[crewrite-arg: add-in-fskey , F , [st, vals, ty, sk, r] → [st, refval(jvmref) ' + vals, ty, sk, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, refval(jvmref) ' + vals, ty, sk, r)]]