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Proof step 83 from proof putarray-addarray-one (previous step)

¬ r0 ≠ r, is_reftype(ty) ⊦ r0 -- sk ∈ addarray(r, ty, n→i(# vals) + 1, st) ∨ r0 = r ∧ is_indexkey(sk) ∧ 0 < sk .index ∧ sk .index ≤ n→i(# vals) ↔ r0 -- sk ∈ addarray(r, ty, refval(jvmref) ' + vals, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 82:
is_reftype(ty) ⊦ r -- sk ∈ addarray(r, ty, n→i(# vals) + 1, st) ∨ is_indexkey(sk) ∧ 0 < sk .index ∧ sk .index ≤ n→i(# vals) ↔ r -- sk ∈ addarray(r, ty, refval(jvmref) ' + vals, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]