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Proof step 16 from proof subset-addarray-01 (previous step)

newref(r, st0), newref(r, st) ⊦ st ⊆ addarray(r, ty, vals, st0) ↔ st ⊆ st0, r = jvmref

User applied rule case distinction

And obtained the following new goals

Proof step 13:
st ⊆ addarray(r, ty, vals, st0), newref(r, st0), newref(r, st) ⊦ st ⊆ st0, r = jvmref
Proof step 15:
st ⊆ st0, newref(r, st0), newref(r, st) ⊦ st ⊆ addarray(r, ty, vals, st0), r = jvmref

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]