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Proof step 17 from proof subset-addarray-01 (conclusion)

⊦ newref(r, st0) ∧ newref(r, st) → (st ⊆ addarray(r, ty, vals, st0) ↔ st ⊆ st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
newref(r, st0), newref(r, st) ⊦ st ⊆ addarray(r, ty, vals, st0) ↔ st ⊆ st0, r = jvmref

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ newref(r, st) → r ≠ jvmref])]]