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Proof step 7 from proof subset-addarray (previous step)

st ⊆ st0, newref(r, st0) ⊦ r = jvmref, ∀ rk. rk ∈ st → rk ∈ addarray(r, ty, vals, st0) ∧ st[rk] = (addarray(r, ty, vals, st0)[rk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
newref(r, st0), st ⊆ st0, rk ∈ st ⊦ r = jvmref, rk ∈ addarray(r, ty, vals, st0) ∧ st[rk] = (addarray(r, ty, vals, st0)[rk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]