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Proof step 8 from proof subset-addarray (previous step)

st ⊆ st0, newref(r, st0) ⊦ r = jvmref, st ⊆ addarray(r, ty, vals, st0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ st1 ⊆ st2 ↔ (∀ rk. rk ∈ st1 → rk ∈ st2 ∧ st1[rk] = st2[rk])
Proof step 7:
st ⊆ st0, newref(r, st0) ⊦ r = jvmref, ∀ rk. rk ∈ st → rk ∈ addarray(r, ty, vals, st0) ∧ st[rk] = (addarray(r, ty, vals, st0)[rk])

Rule argument

[speclemmaarg: ,st1 ⊆ st2 ↔ (∀ rk. rk ∈ st1 → rk ∈ st2 ∧ st1[rk] = st2[rk]) ,[st2, st1] → [addarray(r, ty, vals, st0), st] ,F ,store ,javastore ,Subset ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addarray(r, ty, vals, st0), st)]]