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Proof step 9 from proof subset-addarray (conclusion)

⊦ st ⊆ st0 ∧ newref(r, st0) → st ⊆ addarray(r, ty, vals, st0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
st ⊆ st0, newref(r, st0) ⊦ r = jvmref, st ⊆ addarray(r, ty, vals, st0)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ newref(r, st) → r ≠ jvmref])]]