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Proof step 20 from proof ac-in-08 (previous step)

r ∈ st, is_fskey(sk), ∀ r, st, class1. r ∈ st → r ∈ addclass(class1, fis0, st) ⊦ sk .fs .class = class1, r ∈ addclass(class1, fis0, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 19:
sk = fs ', r ∈ st, is_fskey(sk), ∀ r, st, class1. r ∈ st → r ∈ addclass(class1, fis0, st) ⊦ fs .class = class1, r ∈ addclass(class1, fis0, st)

Rule argument

[speclemmaarg: ,is_fskey(sk) → (fs = sk .fs ↔ sk = fs ') ,[sk, fs] → [sk, fs] ,T ,storekey , ,elim-03 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_fskey(sk) → (fs = sk .fs ↔ sk = fs ')])], [EXTRATERMS : (sk, fs)]]