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Proof step 21 from proof ac-in-08 (previous step)

fv = sk × val, r ∈ st, is_fskey(sk), ∀ r, st, class1. r ∈ st → r ∈ addclass(class1, fis0, st) ⊦ sk .fs .class = class1, r ∈ addclass(class1, fis0, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
r ∈ st, is_fskey(sk), ∀ r, st, class1. r ∈ st → r ∈ addclass(class1, fis0, st) ⊦ sk .fs .class = class1, r ∈ addclass(class1, fis0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]