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Proof step 10 from proof ac-lookup-04 (previous step)

¬ (is_fskey((sk0 × val) .1) ∧ (sk0 × val) .1 .fs .class ≠ class1), is_fskey(sk0), ∀ r, class1, st, sk. r = jvmref ∨ (addclass(class1, fis0, st)[r -- sk]) = st[r -- sk] ⊦ r = jvmref, (addclass(class1, (sk0 × val) ' + fis0, st)[r -- sk]) = st[r -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
is_fskey(sk0), ∀ r, class1, st, sk. r = jvmref ∨ (addclass(class1, fis0, st)[r -- sk]) = st[r -- sk] ⊦ r = jvmref, (addclass(class1, (sk0 × val) ' + fis0, st)[r -- sk]) = st[r -- sk], ¬ is_indexkey(sk0) ∧ sk0 .fs .class ≠ class1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ is_indexkey(sk) ↔ is_fskey(sk)], [CSIMPSEQ : ⊦ ¬ is_fskey(sk) ↔ is_indexkey(sk)], [CSIMPSEQ : ⊦ (sk × val) .1 = sk])]]