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Proof step 17 from proof ac-lookup-04 (previous step)

is_fskey(sk0), ∀ r, class1, st, sk. r = jvmref ∨ (addclass(class1, fis0, st)[r -- sk]) = st[r -- sk] ⊦ r = jvmref, (addclass(class1, (sk0 × val) ' + fis0, st)[r -- sk]) = st[r -- sk]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ is_fskey(fv .1) ∧ fv .1 .fs .class ≠ class → addclass(class, fv ' + fis, st) = addclass(class, fis, st)
Proof step 10:
¬ (is_fskey((sk0 × val) .1) ∧ (sk0 × val) .1 .fs .class ≠ class1), is_fskey(sk0), ∀ r, class1, st, sk. r = jvmref ∨ (addclass(class1, fis0, st)[r -- sk]) = st[r -- sk] ⊦ r = jvmref, (addclass(class1, (sk0 × val) ' + fis0, st)[r -- sk]) = st[r -- sk]
Proof step 16:
is_fskey((sk0 × val) .1) ∧ (sk0 × val) .1 .fs .class ≠ class1, is_fskey(sk0), ∀ r, class1, st, sk. r = jvmref ∨ (addclass(class1, fis0, st)[r -- sk]) = st[r -- sk] ⊦ r = jvmref, (addclass(class1, fis0, st)[r -- sk]) = st[r -- sk]

Rule argument

[crewrite-arg: ac-no1 , F , [st, fis, fv, class] → [st, fis0, sk0 × val, class1] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, fis0, sk0 × val, class1)]]