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Proof step 6 from proof ac-no1 (previous step)

is_fskey(fv .1) ⊦ fv .1 .fs .class = class, addclass(class, fv ' + fis, st) = addclass(class, fis, st)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 5:
fv = sk × val, is_fskey(sk) ⊦ sk .fs .class = class, addclass(class, fv ' + fis, st) = addclass(class, fis, st)

Rule argument

[speclemmaarg: ,sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val ,[fv, sk, val] → [fv, sk, val] ,T ,pair ,fieldinit ,elim ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ sk = fv .1 ∧ val = fv .2 ↔ fv = sk × val])], [EXTRATERMS : (fv, sk, val)]]