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Proof step 7 from proof ac-no1 (conclusion)

⊦ is_fskey(fv .1) ∧ fv .1 .fs .class ≠ class → addclass(class, fv ' + fis, st) = addclass(class, fis, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
is_fskey(fv .1) ⊦ fv .1 .fs .class = class, addclass(class, fv ' + fis, st) = addclass(class, fis, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]