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Proof step 19 from proof ac-refs (previous step)

is_fskey(sk), ∀ class, st. addclass(class, fis0, st) .refs = st .refs ++ jvmref ⊦ addclass(class, fis0, st) .refs = st .refs ++ jvmref, sk .fs .class = class

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 18:
sk = fs ', is_fskey(sk), ∀ class, st. addclass(class, fis0, st) .refs = st .refs ++ jvmref ⊦ addclass(class, fis0, st) .refs = st .refs ++ jvmref, fs .class = class

Rule argument

[speclemmaarg: ,is_fskey(sk) → (fs = sk .fs ↔ sk = fs ') ,[sk, fs] → [sk, fs] ,T ,storekey , ,elim-03 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_fskey(sk) → (fs = sk .fs ↔ sk = fs ')])], [EXTRATERMS : (sk, fs)]]