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Proof step 20 from proof ac-refs (previous step)

is_fskey((sk × val) .1) ∧ (sk × val) .1 .fs .class ≠ class, ∀ class, st. addclass(class, fis0, st) .refs = st .refs ++ jvmref ⊦ addclass(class, fis0, st) .refs = st .refs ++ jvmref

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
is_fskey(sk), ∀ class, st. addclass(class, fis0, st) .refs = st .refs ++ jvmref ⊦ addclass(class, fis0, st) .refs = st .refs ++ jvmref, sk .fs .class = class

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (sk × val) .1 = sk])]]