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Proof step 2 from proof add-field-if (previous step)

⊦ ((sk0 = sk ⊃ val; addobj(r, class1, fis, st)[r -- sk0])) = ((sk = sk0 ⊃ val; addobj(r, class1, fis, st)[r -- sk0]))

Heuristic if-then-else split applied rule case distinction

And closed the goal!

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ()]]