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Proof step 3 from proof add-field-if (conclusion)

⊦ (addobj(r, class1, (sk × val) ' + fis, st)[r -- sk0]) = ((sk = sk0 ⊃ val; addobj(r, class1, fis, st)[r -- sk0]))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ addobj(r, class1, (sk × val) ' + fis, st) = (addobj(r, class1, fis, st)[r -- sk, val])
Proof step 2:
⊦ ((sk0 = sk ⊃ val; addobj(r, class1, fis, st)[r -- sk0])) = ((sk = sk0 ⊃ val; addobj(r, class1, fis, st)[r -- sk0]))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk = r0 -- sk0 ↔ ¬ ¬ (r = r0 ∧ sk = sk0)], [CSIMPSEQ : ⊦ (st[rk0, val][rk]) = ((rk = rk0 ⊃ val; st[rk]))], [CSIMPSEQ : ⊦ (fis + fis0) + fis1 = fis + fis0 + fis1])]]