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Proof step 12 from proof add-gins (previous step)

∀ r, class1, st, sk, val. (addobj(r, class1, fis0, st)[r -- sk, val]) = addobj(r, class1, fis0[sk, val], st) ⊦ (addobj(r, class1, fis0, st)[r -- sk0, val0][r -- sk, val]) = addobj(r, class1, ((sk0 × val0) ' + fis0)[sk, val], st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ sk ≠ sk0 → ((sk0 × val) ' + fis)[sk, val0] = (sk0 × val) ' + fis[sk, val0]
Proof step 5:
⊦ addobj(r, class1, (sk × val) ' + fis, st) = (addobj(r, class1, fis, st)[r -- sk, val])
Proof step 11:
sk ≠ sk0, ∀ r, class1, st, sk, val. (addobj(r, class1, fis0, st)[r -- sk, val]) = addobj(r, class1, fis0[sk, val], st) ⊦ (addobj(r, class1, fis0, st)[r -- sk0, val0][r -- sk, val]) = addobj(r, class1, (sk0 × val0) ' + fis0[sk, val], st)

Rule argument

[speclemmaarg: , sk ≠ sk0 → ((sk0 × val) ' + fis)[sk, val0] = (sk0 × val) ' + fis[sk, val0] ,[val0, sk, fis, val, sk0] → [val, sk, fis0, val0, sk0] ,F ,assoclist ,fieldinit ,put-no ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ (st[rk, val][rk, val0]) = st[rk, val0]], [CSIMPSEQ : ⊦ ((sk × val) ' + fis)[sk, val0] = (sk × val0) ' + fis], [CSIMPSEQ : ⊦ (fis + fis0) + fis1 = fis + fis0 + fis1])], [EXTRATERMS : (val, sk, fis0, val0, sk0)]]