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Proof step 13 from proof add-gins (previous step)

fv = sk0 × val0, ∀ r, class1, st, sk, val. (addobj(r, class1, fis0, st)[r -- sk, val]) = addobj(r, class1, fis0[sk, val], st) ⊦ (addobj(r, class1, fis0, st)[r -- sk0, val0][r -- sk, val]) = addobj(r, class1, (fv ' + fis0)[sk, val], st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
∀ r, class1, st, sk, val. (addobj(r, class1, fis0, st)[r -- sk, val]) = addobj(r, class1, fis0[sk, val], st) ⊦ (addobj(r, class1, fis0, st)[r -- sk0, val0][r -- sk, val]) = addobj(r, class1, ((sk0 × val0) ' + fis0)[sk, val], st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]