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Proof step 45 from proof addobj-addclass-sw (previous step)

¬ ¬ is_fskey(sk) ⊦ jvmref = r, (jvmref -- sk ∈ addclass(class0, fis0, st) ↔ jvmref -- sk ∈ addclass(class0, fis0, addobj(r, class, fis, st))) ∧ (addclass(class0, fis0, st)[jvmref -- sk]) = (addclass(class0, fis0, addobj(r, class, fis, st))[jvmref -- sk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 44:
is_fskey(sk) ⊦ jvmref = r, (jvmref -- sk ∈ addclass(class0, fis0, st) ↔ jvmref -- sk ∈ addclass(class0, fis0, addobj(r, class, fis, st))) ∧ (addclass(class0, fis0, st)[jvmref -- sk]) = (addclass(class0, fis0, addobj(r, class, fis, st))[jvmref -- sk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]