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Proof step 55 from proof addobj-addclass-sw (previous step)

⊦ jvmref = r, (jvmref -- sk ∈ addclass(class0, fis0, st) ↔ jvmref -- sk ∈ addclass(class0, fis0, addobj(r, class, fis, st))) ∧ (addclass(class0, fis0, st)[jvmref -- sk]) = (addclass(class0, fis0, addobj(r, class, fis, st))[jvmref -- sk])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 22:
⊦ ¬ is_fskey(sk) → (r -- sk ∈ addclass(class, fis, st) ↔ r -- sk ∈ st)
Proof step 45:
¬ ¬ is_fskey(sk) ⊦ jvmref = r, (jvmref -- sk ∈ addclass(class0, fis0, st) ↔ jvmref -- sk ∈ addclass(class0, fis0, addobj(r, class, fis, st))) ∧ (addclass(class0, fis0, st)[jvmref -- sk]) = (addclass(class0, fis0, addobj(r, class, fis, st))[jvmref -- sk])
Proof step 54:
¬ is_fskey(sk) ⊦ jvmref = r, (jvmref -- sk ∈ st ↔ jvmref -- sk ∈ addclass(class0, fis0, addobj(r, class, fis, st))) ∧ (addclass(class0, fis0, st)[jvmref -- sk]) = (addclass(class0, fis0, addobj(r, class, fis, st))[jvmref -- sk])

Rule argument

[crewrite-arg: ac-in-11 , F , [st, fis, class, sk, r] → [st, fis0, class0, sk, jvmref] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, fis0, class0, sk, jvmref)]]