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Proof step 19 from proof addobj-delsw (previous step)

¬ r1 -- sk ∈ addobj(r0, class, fis, st) -- r1 ⊦ r1 = r0, ∅[r1 -- sk] = (st -- r1)[r1 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
⊦ r1 = r0, noval = (st -- r1)[r1 -- sk], r1 -- sk ∈ addobj(r0, class, fis, st) -- r1

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ∅[rk] = noval])]]