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Proof step 20 from proof addobj-delsw (previous step)

⊦ r1 = r0, (addobj(r0, class, fis, st) -- r1)[r1 -- sk] = (st -- r1)[r1 -- sk]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ ¬ rk ∈ st → st[rk] = ∅[rk]
Proof step 19:
¬ r1 -- sk ∈ addobj(r0, class, fis, st) -- r1 ⊦ r1 = r0, ∅[r1 -- sk] = (st -- r1)[r1 -- sk]

Rule argument

[speclemmaarg: ,¬ rk ∈ st → st[rk] = ∅[rk] ,[rk, st] → [r1 -- sk, addobj(r0, class, fis, st) -- r1] ,F ,store ,javastore ,notmemlookup ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r -- sk ∈ st -- r0 ↔ r ≠ r0 ∧ r -- sk ∈ st])], [EXTRATERMS : (r1 -- sk, addobj(r0, class, fis, st) -- r1)]]