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Proof step 21 from proof addobj-delsw (previous step)

¬ r ≠ r1 ⊦ r = r0, r1 = r0, (addobj(r0, class, fis, st) -- r)[r1 -- sk] = (st -- r)[r1 -- sk]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
⊦ r1 = r0, (addobj(r0, class, fis, st) -- r1)[r1 -- sk] = (st -- r1)[r1 -- sk]

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]