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Proof step 23 from proof addobj-delsw (previous step)

⊦ r = r0, r1 = r0, (addobj(r0, class, fis, st) -- r)[r1 -- sk] = (st -- r)[r1 -- sk]

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ r ≠ r0 → (st -- r)[r0 -- sk0] = st[r0 -- sk0]
Proof step 21:
¬ r ≠ r1 ⊦ r = r0, r1 = r0, (addobj(r0, class, fis, st) -- r)[r1 -- sk] = (st -- r)[r1 -- sk]
Proof step 22:
⊦ r ≠ r0 → (addobj(r, class1, fis, st)[r0 -- sk]) = st[r0 -- sk]

Rule argument

[speclemmaarg: ,r ≠ r0 → (st -- r)[r0 -- sk0] = st[r0 -- sk0] ,[sk0, r0, r, st] → [sk, r1, r, addobj(r0, class, fis, st)] ,F ,storefuns , ,look-del ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ≠ r0 → (st -- r)[r0 -- sk0] = st[r0 -- sk0]])], [EXTRATERMS : (sk, r1, r, addobj(r0, class, fis, st))]]