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Proof step 8 from proof addobj-isarray (previous step)

⊦ r = r0, r ≠ jvmref ∧ r -- _type ∈ addobj(r0, class, fis, st) ∧ is_typevalue(addobj(r0, class, fis, st)[r -- _type]) ∧ is_arraytype((addobj(r0, class, fis, st)[r -- _type]) .type) ∧ okarray(r, (addobj(r0, class, fis, st)[r -- _type]) .type .type, addobj(r0, class, fis, st)) ↔ is_array(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ r ≠ r0 → (r -- sk ∈ addobj(r0, class1, fis, st) ↔ r -- sk ∈ st)
Proof step 3:
⊦ r ≠ r0 → (addobj(r, class1, fis, st)[r0 -- sk]) = st[r0 -- sk]
Proof step 7:
⊦ r = r0, r ≠ jvmref ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_arraytype(st[r -- _type] .type) ∧ okarray(r, st[r -- _type] .type .type, addobj(r0, class, fis, st)) ↔ is_array(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]