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Proof step 9 from proof addobj-isarray (previous step)

⊦ r = r0, is_array(r, addobj(r0, class, fis, st)) ↔ is_array(r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_array(r, st) ↔ r ≠ jvmref ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_arraytype(st[r -- _type] .type) ∧ okarray(r, st[r -- _type] .type .type, st)
Proof step 8:
⊦ r = r0, r ≠ jvmref ∧ r -- _type ∈ addobj(r0, class, fis, st) ∧ is_typevalue(addobj(r0, class, fis, st)[r -- _type]) ∧ is_arraytype((addobj(r0, class, fis, st)[r -- _type]) .type) ∧ okarray(r, (addobj(r0, class, fis, st)[r -- _type]) .type .type, addobj(r0, class, fis, st)) ↔ is_array(r, st)

Rule argument

[speclemmaarg: , is_array(r, st) ↔ r ≠ jvmref ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_arraytype(st[r -- _type] .type) ∧ okarray(r, st[r -- _type] .type .type, st) ,[st, r] → [addobj(r0, class, fis, st), r] ,F ,okfuns , ,is-any-array ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addobj(r0, class, fis, st), r)]]