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Proof step 11 from proof addobj-union-rew (previous step)

¬ sk ∈ fis, newref(r0, st0), newref(r0, st) ⊦ (addobj(r0, class, fis, st ∪ st0)[r0 -- sk]) = (st ∪ addobj(r0, class, fis, st0))[r0 -- sk], r0 = jvmref, ¬ sk ∈ fis ∧ sk ≠ _type

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
¬ _type ∈ fis ⊦ (addobj(r, class1, fis, st)[r -- _type]) = typeval(mkclasstype(class1))
Proof step 10:
newref(r0, st), newref(r0, st0) ⊦ r0 = jvmref, typeval(mkclasstype(class)) = (st ∪ addobj(r0, class, fis, st0))[r0 -- _type], _type ∈ fis

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]