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Proof step 17 from proof addobj-union-rew (previous step)

newref(r0, st0), newref(r0, st) ⊦ (addobj(r0, class, fis, st ∪ st0)[r0 -- sk]) = (st ∪ addobj(r0, class, fis, st0))[r0 -- sk], r0 = jvmref, ¬ sk ∈ fis ∧ sk ≠ _type

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ sk ∈ fis → (addobj(r, class, fis, st)[r -- sk]) = fis[sk]
Proof step 11:
¬ sk ∈ fis, newref(r0, st0), newref(r0, st) ⊦ (addobj(r0, class, fis, st ∪ st0)[r0 -- sk]) = (st ∪ addobj(r0, class, fis, st0))[r0 -- sk], r0 = jvmref, ¬ sk ∈ fis ∧ sk ≠ _type
Proof step 16:
sk ∈ fis, newref(r0, st0), newref(r0, st) ⊦ fis[sk] = (st ∪ addobj(r0, class, fis, st0))[r0 -- sk], r0 = jvmref, ¬ sk ∈ fis ∧ sk ≠ _type

Rule argument

[crewrite-arg: add-in-09 , F , [sk, st, fis, class, r] → [sk, st ∪ st0, fis, class, r0] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk, st ∪ st0, fis, class, r0)]]