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Proof step 14 from proof stsubset-addobj (previous step)

rk ∈ st, newref(r, st), ∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk] ⊦ r = jvmref, rk ∈ st0, rk ∈ addobj(r, class1, fis, st0) ∧ st[rk] = (addobj(r, class1, fis, st0)[rk])

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 3, [QUANTTERMLIST : (rk)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (rk)]]