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Proof step 15 from proof stsubset-addobj (previous step)

¬ rk ∈ st0, newref(r, st), rk ∈ st, ∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk] ⊦ r = jvmref, rk ∈ addobj(r, class1, fis, st0) ∧ st[rk] = (addobj(r, class1, fis, st0)[rk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
rk ∈ st, newref(r, st), ∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk] ⊦ r = jvmref, rk ∈ st0, rk ∈ addobj(r, class1, fis, st0) ∧ st[rk] = (addobj(r, class1, fis, st0)[rk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]