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Proof step 23 from proof stsubset-addobj (previous step)

newref(r, st), rk ∈ st, ∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk] ⊦ r = jvmref, rk ∈ addobj(r, class1, fis, st0) ∧ st[rk] = (addobj(r, class1, fis, st0)[rk])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ rk ∈ st → rk ∈ addobj(r, class1, fis, st)
Proof step 15:
¬ rk ∈ st0, newref(r, st), rk ∈ st, ∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk] ⊦ r = jvmref, rk ∈ addobj(r, class1, fis, st0) ∧ st[rk] = (addobj(r, class1, fis, st0)[rk])
Proof step 22:
rk ∈ st0, newref(r, st), rk ∈ st, ∀ rk. rk ∈ st → rk ∈ st0 ∧ st[rk] = st0[rk] ⊦ r = jvmref, true ∧ st[rk] = (addobj(r, class1, fis, st0)[rk])

Rule argument

[crewrite-arg: add-in-03 , F , [st, fis, class1, r, rk] → [st0, fis, class1, r, rk] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st0, fis, class1, r, rk)]]