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Proof step 5 from proof validref-del-01 (previous step)

⊦ r = r0, is_obj(r, st -- r0) ∨ is_array(r, st -- r0) ↔ is_valid_ref(r, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ r ≠ r0 → (is_obj(r0, st -- r) ↔ is_obj(r0, st))
Proof step 4:
⊦ r = r0, is_obj(r, st) ∨ is_array(r, st) ↔ is_valid_ref(r, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ≠ r0 → ( is_array(r0, st -- r) ↔ is_array(r0, st))])]]