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Proof step 6 from proof validref-del-01 (previous step)

⊦ r = r0, is_valid_ref(r, st -- r0) ↔ is_valid_ref(r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_valid_ref(r, st) ↔ is_obj(r, st) ∨ is_array(r, st)
Proof step 5:
⊦ r = r0, is_obj(r, st -- r0) ∨ is_array(r, st -- r0) ↔ is_valid_ref(r, st)

Rule argument

[crewrite-arg: is-valid-ref, F, [st, r] → [st -- r0, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st -- r0, r)]]