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Proof step 10 from proof compatval-put (previous step)

okval(refval(r), ty), r -- _type ∈ st, is_typevalue(st[r -- _type]), is_reftype(st[r -- _type] .type), asgcomp(str, refval(r), ty, st), r ∈ st, has_classtype(st[r -- _type] .type) → tdname+∃(str, st[r -- _type] .type .jtelemtype .class), is_classtype(st[r -- _type] .type) → class+∃(str, st[r -- _type] .type .class) ⊦ ty0 = void_type, r = jvmref, ( has_classtype(st[r -- _type] .type) → class∃(str, st[r -- _type] .type .jtelemtype .class) ∨ interface∃(str, st[r -- _type] .type .jtelemtype .class) ∨ is_predefined_class(st[r -- _type] .type .jtelemtype .class)) ∧ is_subtype(str, st[r -- _type] .type, ty)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 9:
st[r -- _type] = typeval(ty1), okval(refval(r), ty), r -- _type ∈ st, is_typevalue(st[r -- _type]), is_reftype(ty1), asgcomp(str, refval(r), ty, st), r ∈ st, has_classtype(ty1) → tdname+∃(str, ty1 .jtelemtype .class), is_classtype(ty1) → class+∃(str, ty1 .class) ⊦ ty0 = void_type, r = jvmref, (has_classtype(ty1) → class∃(str, ty1 .jtelemtype .class) ∨ interface∃(str, ty1 .jtelemtype .class) ∨ is_predefined_class(ty1 .jtelemtype .class)) ∧ is_subtype(str, ty1, ty)

Rule argument

[speclemmaarg: ,is_typevalue(val) → (ty = val .type ↔ val = typeval(ty)) ,[val, ty] → [st[r -- _type], ty1] ,T ,javavalue , ,elim-10 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_typevalue(val) → ( ty = val .type ↔ val = typeval(ty))])], [EXTRATERMS : (st[r -- _type], ty1)]]